Respuesta :
Answer:
The fundamental frequency will increase to 1782.69 Hz
Explanation:Fundamental frequency of the pipe when filled with air:
[tex]f_{\text{air}}=660Hz[/tex]Speed of sound in air:
[tex]v_{\text{air}}=343\text{ m/s}[/tex]The wavelength is calculated as shown below
[tex]\begin{gathered} v_{\text{air}}=\lambda f_{air} \\ 343=\lambda(660) \\ \lambda=\frac{343}{660} \\ \lambda=0.52m \end{gathered}[/tex]If the closed pipe is filled with helium
Speed of sound in Helium
[tex]v_{He}=927\text{ m/s}[/tex]The new fundamental frequency is calculated below:
[tex]\begin{gathered} v_{He}=\lambda f_{He} \\ 927=0.52f_{He} \\ f_{He}=\frac{927}{0.52} \\ f_{He}=1782.69Hz \end{gathered}[/tex]As seen from the calculation above, the fundamental frequency will increase if the closed piper is filled with helium
