ANSWER:
6
STEP-BY-STEP EXPLANATION:
Given:
When x = 16, y = 4
We know that it varies directly with the square root of x, so we can state the following:
[tex]y=k\cdot\sqrt[]{x}[/tex]
We substitute and calculate k, just like this:
[tex]\begin{gathered} 4=k\sqrt[]{16} \\ k=\frac{4}{\sqrt[]{16}} \\ k=\frac{4}{4}=1 \\ \text{ Therefore, the function is} \\ y=\sqrt[]{x} \end{gathered}[/tex]
Now, we calculate the value of y when x = 16 substituting in the function obtained, just like this:
[tex]\begin{gathered} y=\sqrt[]{36} \\ y=6 \end{gathered}[/tex]
The value of y is 6
