Using the distance formula:
[tex]d=\sqrt{(y2-y1)^2+(x2-x1)^2}[/tex]Where
(x1, y1)==> (12, 8)
(x2, y2) ==>(4, 2)
Substitute the values into the distance formula above;
[tex]\begin{gathered} d=\text{ }\sqrt{(2-8)^2+(4-12)^2} \\ \\ \text{ = }\sqrt{(-6)^2+(-8)^2} \\ \\ =\text{ }\sqrt{36+64} \\ \\ =\sqrt{100} \\ \\ =10 \end{gathered}[/tex]Therefore the distance is 10 units
ANSWER:
B) 10 units
