Answer:
19/10 miles
Explanation:
The situation is sketched below
The remaining distance is
[tex]4\frac{1}{2}-2\frac{3}{5}[/tex]which can be rewritten as
[tex]4+\frac{1}{2}-2-\frac{3}{5}[/tex][tex]2+\frac{1}{2}-\frac{3}{5}[/tex]We subtract the fractions 1/2 and 3/5.
[tex]\frac{1}{2}\cdot\frac{5}{5}-\frac{3}{5}\cdot\frac{2}{2}[/tex][tex]=\frac{5}{10}-\frac{6}{10}=-\frac{1}{10}[/tex]Therefore now our expression becomes
[tex]2+\frac{1}{2}-\frac{3}{5}=2-\frac{1}{10}[/tex]which can be further rewritten as
[tex]2\cdot\frac{10}{10}-\frac{1}{10}[/tex][tex]=\frac{20}{10}-\frac{1}{10}[/tex][tex]=\frac{19}{10}[/tex]which is our answer!
