[tex]y \ \textless \ x + 3[/tex][tex]y \leqslant - 3x - 5[/tex]Solve The following system of inequalities graphically on the set of axes. State the coordinates of a point in the solution set.

Respuesta :

[tex]\begin{gathered} yThe solutions are:

[tex]\begin{gathered} x>-2,_{\text{ }}y\le3x-5 \\ x\le-2,_{\text{ }}yWe can find the x-intercept and y-intercept for y < x + 3 :

The y-intercept is:

[tex]\begin{gathered} x=0 \\ y=0+3 \\ y=3 \\ (0,3) \end{gathered}[/tex]

The x-intercept is:

[tex]\begin{gathered} y=0 \\ 0=x+3 \\ x=-3 \\ (-3,0) \end{gathered}[/tex]

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For y ≤-3x-5

The y-intercept is:

[tex]\begin{gathered} x=0 \\ y=-3(0)-5 \\ y=-5 \\ (0,-5) \end{gathered}[/tex]

The x-intercept is:

[tex]\begin{gathered} y=0 \\ 0=-3x-5 \\ x=-\frac{5}{3}=-1.667 \\ (-1.667,0) \end{gathered}[/tex]

Ver imagen RakanD537977
Ver imagen RakanD537977