Let's begin by listing out the information given to us:
Total number of hats = 20
Number of green hats = 5
Number of blue hats = 8
Number of orange hats = 7
The probability of choosing 2 blue hats in a row without replacement is calculated as shown below:
[tex]\begin{gathered} For\text{ the first choosing, we have:} \\ P(blue)=\frac{No\mathrm{}Of\mathrm{}BlueHats}{TotalHats}=\frac{8}{20}=\frac{2}{5} \\ P(blue)=\frac{2}{5} \\ \\ \text{For the second choosing, we have:} \\ P(blue)=\frac{NoOfBlueHats(Left)}{TotalHats(Left)}=\frac{7}{19} \\ P(blue)=\frac{7}{19} \\ \\ The\text{ probability of choosing two blue hats in a row is:} \\ P(TwoBlueHatInARow)=\frac{2}{5}\times\frac{7}{19}=\frac{14}{95} \\ P(TwoBlueHatInARow)=\frac{14}{95} \end{gathered}[/tex]