Solution
We have the following expression:
[tex]\frac{2x}{x+5}\le0[/tex]
We know that denominator needs to satisfy this:
[tex]x+5\ne0[/tex]
Then:
[tex]x\ne-5[/tex]
And the other critical value would be 0 so we have this:
Then the final solution would be.
[tex]\lbrack-5,0\rbrack[/tex]
