Tatiana invests $1300 in one account with rate r
and $2400 in an account paying 3% higher interest (rate: r+0.03)
At the end of the year she had earned $183 In interest:
[tex]1300r+2400(r+0.03)=183[/tex]Use the equation above to solve r:
[tex]\begin{gathered} 1300r+2400r+72=183 \\ 3700r+72=183 \\ 3700r+72-72=183-72 \\ 3700r=111 \\ \\ \frac{3700}{3700}r=\frac{111}{3700} \\ \\ r=0.03 \end{gathered}[/tex]Then, Use the value of r to find the interest rate of second account:
[tex]r+0.03=0.03+0.03=0.06[/tex]Then, multiply each rate you get for first and second account by 100 to get the invest rate in %
$1300 invest at 3%$2400 invested at 6%