Given data:
The given rate is r=4.3%.
The expression for the final population is,
[tex]P=P_0e^{rt}[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} 2P_0=P_0e^{0.043t} \\ 2=e^{0.043t} \\ \ln 2=0.043t \\ t=16.119 \\ =16.1 \end{gathered}[/tex]Thus, the value of time is 16.1 years.
