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Edwardo applies a 4.8 N rightward force to a 1.45 kg book to accelerate it across a tabletop. The force of friction between the book and table is 3.0 N. Determine the acceleration of the book. Round to 4 decimal places if needed

Respuesta :

Answer: acceleration = 1.2414 m/s^2

Explanation:

The diagram representing the scenario is shown below

Recall

Acceleration = net force/mass

Net force = right ward force - frictional force

From the information given,

right ward force = 4.8

frictional force = 3

mass = 1.45

Net force = 4.8 - 3 = 1.8

acceleration = 1.8/1.45

acceleration = 1.2414 m/s^2

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