To find the equation of a line that passes through the point (2, -3) with a slope m = -3.
1. We need to use the Point-Slope Form of the line. Then, we have:
[tex]y-y_1=m(x-x_{1)}\Rightarrow y-(-3)=-3\cdot(x-2)[/tex]In this equation, we have that:
x1 = 2, and y1 = -3
Then, solving the equation, we have:
[tex]y+3=-3x+6\Rightarrow y=-3x+6-3\Rightarrow y=-3x+3_{}[/tex]Therefore, the equation of the line in the Slope-Intercept Form is:
[tex]y=-3x+3[/tex]