ANSWER :
B.
EXPLANATION :
From the problem, we have :
[tex]\frac{2x^{-4}}{3xy}[/tex]
Note that in dividing variables with exponents, the exponents are subtracted.
and any negative exponents will be moved either from numerator to denominator or denominator to numerator.
That will be :
[tex]\begin{gathered} \frac{2x^{-4-1}}{3y}=\frac{2x^{-5}}{3y} \\ \text{ Move the variable with negative exponent from numerator to denominator} \\ =\frac{2}{3x^5y} \end{gathered}[/tex]
The answer is B.
