To answer this question, we need to substitute the value of x = 16 in the given function, and then do the required operations to get the solution. Then, we have:
[tex]f(16)=\frac{1}{3}(4-16)^2\Rightarrow f(16)=\frac{1}{3}(-12)^2\Rightarrow f(16)=\frac{1}{3}\cdot144^{}\Rightarrow f(16)=48[/tex]
Therefore, the value for the function when f(16) is 48.
