ANSWER
E[X] = 1.76
EXPLANATION
The expected value of a discrete data set is the sum of the products of each value by its probability. We have in this case:
• P(0) = 0.24
,• P(1) = 0.24
,• P(2) = 0.19
,• P(3) = 0.18
,• P(4) = 0.15
The expected value in this problem is:
[tex]\begin{gathered} E\lbrack X\rbrack=0\cdot0.24+1\cdot0.24+2\cdot0.19+3\cdot0.18+4\cdot0.15 \\ E\lbrack X\rbrack=0+0.24+0.38+0.54+0.6 \\ E\lbrack X\rbrack=1.76 \end{gathered}[/tex]