SOLUTIONS
A community college are normally distributed with a mean of
48.5 and a standard deviation of 12.4.
[tex]Z_{score}=\frac{x-\mu}{\sigma}[/tex][tex]\begin{gathered} x=40 \\ \mu=48.5 \\ \sigma=12.4 \end{gathered}[/tex][tex]Z_{score}=\frac{40-48.5}{12.4}=-0.685[/tex]Therefore the percentage of the professor younger than 40 is
P(x<40) = 0.24652
[tex]0.24652\text{ }\times100=24.65\text{\%}[/tex]Answer = 24.65%
