[tex]\frac{(x+2)^2}{49}+\frac{(y-1)^2}{25}=1[/tex]
This represents an ellipse, the foci can be calculated as follows:
[tex]\begin{gathered} f=(h\pm c,k) \\ where: \\ h=-2 \\ k=1 \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{49-25} \\ c=\sqrt{24}=2\sqrt{6} \\ Therefore: \\ f=(-2\pm2\sqrt{6},1) \end{gathered}[/tex]
Answer:
B
