I need help with this question, I think its the second option Im not sure tho.

Explanation
Similar triangles are triangles that have the same shape, but their sizes may vary
So for the triangles ABC AND AKY
We can compare similar sides using the ratio:
[tex]\begin{gathered} \frac{AC}{AY}=\frac{7}{2} \\ \\ where \\ AC=28 \\ \\ \frac{28}{AY}=\frac{7}{2} \\ \end{gathered}[/tex]If we solve for AY
[tex]\begin{gathered} AY=\frac{28\times2}{7} \\ \\ AY=4\times2 \\ \\ AY=8 \end{gathered}[/tex]The answer is