Given:
a.) The line pass through the given point (-2, 10).
b.) Slope of the line: -3/2
Step 1: Let's determine the y-intercept (b). Substitute m = -3/2 and x, y = -2, 10 in y = mx + b.
[tex]\text{ y = mx + b}[/tex][tex]\text{ 10 = (-}\frac{3}{2})(-2)\text{ + b}[/tex][tex]\text{ 10 = 3 + b}[/tex][tex]\text{ b = 10 - 3}[/tex][tex]\text{ b = 7}[/tex]Step 2: Let's complete the question. Substitute m = -3/2 and b = 7 in y = mx + b.
[tex]\text{ y = mx + b}[/tex][tex]\text{ y = (-}\frac{3}{2})\text{x + (7)}[/tex][tex]\text{ y = -}\frac{3}{2}\text{x + 7}[/tex]Therefore, the equation of the line is y = -3x/2 + 7
