Given
[tex]\frac{a^2-10}{2}+b,a=4,b=-5[/tex]
Find
Evaluate the expression
Explanation
substitute the value of a and b in given expression.
[tex]\begin{gathered} \frac{a^2-10}{2}+b \\ \frac{(4)^2-10}{2}+(-5) \\ \frac{16-10}{2}-5 \\ \frac{6}{2}-5 \\ 3-5 \\ -2 \end{gathered}[/tex]
Final Answer
Therefore , the correct option is d.
