Given:
The force applied to the box is F = 3 N
The displacement of the box is d = 2 m
The box moves with constant speed.
Required:
1) Work done by Joe on the box.
2) Work done by friction on the box.
Explanation:
1) The work done by Joe on the box can be calculated as
[tex]\begin{gathered} W=Fd \\ =3\times2 \\ =\text{ 6 J} \end{gathered}[/tex]2) The box moves at a constant speed, so the acceleration will be zero.
The equation of motion can be written as
[tex]\begin{gathered} F-f=ma \\ F-f=m\times0 \\ F-f=0 \\ F=f \end{gathered}[/tex]Here, f is the force of friction and m is the mass of the box.
The work done by friction can be calculated as
[tex]\begin{gathered} W=fd \\ =3\times2 \\ =6\text{ J} \end{gathered}[/tex]Final Answer:
1) Work done by Joe on the box is 6 J.
2) Work done by friction on the box is 6 J.
