14.Find the missing side length to the near tenth.х64°6A. 3.1B. 2.6C.13.7D.3.8

90+64+y=180 (sum of angle in a triangle)
The third angle is 26
[tex]\begin{gathered} \frac{x}{\sin26}=\frac{6}{\sin 90} \\ \frac{x}{0.4384}=\frac{6}{1} \\ \text{cross multiply} \\ x\times1=6\times0.4384 \\ x=2.6\text{ nearest tenth} \end{gathered}[/tex]Alternative method
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