Given that
[tex]\begin{gathered} F(x)=x^2-19 \\ G(x)=5-x \end{gathered}[/tex]Then
[tex](\frac{F}{G})(x)=\frac{x^2-19}{5-x}[/tex][tex]\begin{gathered} (\frac{F}{G})(-4)=\frac{(-4)^2-19}{5-(-4)} \\ \\ =\frac{16-19}{5+4} \\ \\ =-\frac{3}{9} \end{gathered}[/tex]