To calculate the height of the building, we will use the trigonometric ratio
[tex]\tan \theta=\frac{opposite}{adjacent}[/tex]
where the values are given
[tex]\begin{gathered} \text{opposite}=\text{ height of the building=x} \\ \text{adjacent}=120ft \\ \theta=68^0 \end{gathered}[/tex]
By substituting the values, we will have
[tex]\begin{gathered} \tan 68^0=\frac{x}{120ft} \\ x=120ft\times\tan 68^0 \\ x=120ft\times2.475 \\ x=297.0ft \\ \text{approcimately to the nearest foot} \\ x=297ft \end{gathered}[/tex]
Hence,
The height of the building =297ft
The correct answer is OPTION B
