Two long, parallel wires separated by 0.199 m carry equal currents of 10.994 A in the same direction. Find the magnitude of the net magnetic field 0.244 m away from each wire on the side opposite the other wire . Express your answer in microTesla.

Respuesta :

We will have the following:

[tex]\begin{gathered} B_1=B_2=\frac{(4\pi\ast10^{-7}Tm/A)(10.944A)}{2\pi(0.244m)} \\ \\ \Rightarrow B_1=9.01147541...\ast10^{-6}T\Rightarrow B_1\approx9\mu T \end{gathered}[/tex]

Then:

[tex]\begin{gathered} B_{net}=\sqrt{(9\mu T)^2+(9\mu T)^2-2(9\mu T)(9\mu T)cos(48.132)}\Rightarrow B_{net}=7.340196633...\mu T \\ \\ \Rightarrow B_{net}\approx7.34\mu T \end{gathered}[/tex]

So, the net magnetic field is approximately 7.34 micro tesla.