contestada

A ship traveled halfway to its destinationat 18 knots (nautical miles per hour)and then increased its speed to 22 knotsfor the rest of the voyage. If the sec-ond half of the trip was completed in 2hours less, how far did it travel at 18knots? How far was the voyage?

Respuesta :

Given:

Half of the voyage is traveled in 18 knots.

The remaining half of the voyage is traveled in 22 knots.

The second half of the trip was completed in 2 hours less than the first half of the trip.

So, the equation is,

[tex]\begin{gathered} \frac{D}{18}-\frac{D}{22}=2 \\ \frac{22D-18D}{(18)(22)}=2 \\ \frac{4D}{(18)(22)}=2 \\ D=9\times11\times2 \\ D=198\text{ nautical miles} \end{gathered}[/tex]

So, the distance traveled at 18 knots is 198 nautical miles.

And hence, the total distance of the trip is 396 nautical miles.

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