The plans for a new ammusement park were laid out on the first quadrant of a coordinate plane. The entrance to the roller coaster was shown at (1, 1), and the entrance to the bumper cars was shown at (7,9).

The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
[tex]\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}[/tex]Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters