Problem
Solution
for this case we know that when x =2/3 , y= 6
[tex]10\frac{1}{3}=\frac{10\cdot3+1}{3}=\frac{30+1}{3}=\frac{31}{3}[/tex]Then we want to find the value of y= ? when x= 10 1/3 = 31/3 and we can do this:
6/(2/3) = y/(31/3)
[tex]\frac{6}{\frac{2}{3}}=\frac{y}{\frac{31}{3}}[/tex][tex]y=\frac{31}{3}\cdot\frac{6}{\frac{2}{3}}=\frac{31}{3}\cdot\frac{3}{2}\cdot\frac{6}{1}=\frac{31\cdot3\cdot6}{3\cdot2\cdot1}=93[/tex]And solving for y we got:
y = (3/2) * 6 * (31/3) = 31*3 = 93
C. y= 93
