Line C
Point C1 = (x1,y1)= (5,4)
Point C2 = (x2,y2) = (9,16)
Apply the slope (m) formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]_Replace:
[tex]m=\frac{16-4}{9-5}=\frac{12}{4}=3[/tex]Same process for Line d:
Pont d1= (-2,9) = (x1,y1)
Point d2 = (1,18) = (x2,y2)
[tex]m=\frac{18-9}{1-(-2)}=\frac{18-9}{1+2}=\frac{9}{3}=3[/tex]Both lines have the same slope (3), so, both lines are parallel.
