Given the cubic function
[tex]x^3-3x^2-4x+12[/tex]
To get the other factors using the long division method
Having obtained the result of
[tex]\begin{gathered} div\text{iding } \\ x^3-3x^2-4x+12 \\ by \\ x-2 \end{gathered}[/tex]
which gives x²-x-6
The next step will be to factor x²-x-6
[tex]x^2-x-6=(x+2)(x-3)[/tex]
Combining the factors, we will obtain
[tex](x-2)(x+2)(x-3)[/tex]
The answer is option 3
