Given
The points are given
[tex](-2,3),(1,4)[/tex]
Explanation
To determine the equation in slope-intercept form,
Use the general form ,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Substitute the coordinates in the general form.
[tex]\begin{gathered} y-3=\frac{4-3}{1-(-2)}(x-(-2)) \\ y-3=\frac{1}{3}(x+2) \\ y=\frac{1}{3}x+\frac{2}{3}+3 \\ y=\frac{x}{3}+\frac{2+9}{3} \\ y=\frac{x}{3}+\frac{11}{3} \end{gathered}[/tex]
Answer
Hence the slope-intercept form is
[tex]y=\frac{x}{3}+\frac{11}{3}[/tex]
