The following table is a valid probability distribution for a random variable X. What must be the value forP(2) to complete the table?X0123a. 0.15b. 0.2P(X)0.150.20.4C. 0.25d.0.3

Given:
There are given the table of probability distribution to find the value of p(2).
Explanation:
To find the value of the probability distribution of p(2), we need to use their formula:
So,
From the formula:
[tex]P(2)=1-(x_{0}p(x_{0})+x_{1}p(x_{1})+x_{3}p(x_{3}))[/tex]So,
Put all the values one by one from the table into the given formula:
So,
[tex]\begin{gathered} P(2)=1-(x_0p(x_0)+x_1p(x_1)+x_3p(x_3)) \\ =1-(0.15+0.2+0.4) \\ =1-(0.75) \\ =0.25 \end{gathered}[/tex]
Final answer:
Hence, the value of p(2) is 0.25.