[tex]y=-\frac{6}{5}x-2[/tex]
Check the graph below, please
1) Since we have the equation in the Standard form we can manipulate it so that we can have the slope-intercept form:
[tex]-6x-5y=10[/tex]
Let's isolate the y-term on the left:
[tex]\begin{gathered} -6x-5y=10 \\ -5y=10+6x \\ \frac{-5y}{-5}=\frac{10}{-5}+\frac{6x}{-5} \\ y=-\frac{6}{5}x-2 \end{gathered}[/tex]
2) Now, let's plot the line of this function, by picking values for x and inserting them to get the value of y. We can write out the T table:
x|y
-1y=-6/5(-1)-2 => y=-0.8
0 | -2
1 |-3.2
With the points (-1, -0.8), (0,-2) and (1,-3.2) we can trace a decreasing line:
for the slope m is negative.
3) Hence, these are the answers above:
