Let:
[tex]\begin{gathered} (x1,y1)=(-3,0) \\ (x2,y2)=(0,-3) \end{gathered}[/tex]
The slope m is given by:
[tex]m=\frac{y2-y1}{x2-x1}=\frac{-3-0}{0-(-3)}=\frac{-3}{3}=-1[/tex]
Using the point-slope equation:
[tex]\begin{gathered} y-y1=m(x-x1) \\ y-0=-1(x-(-3)) \\ y=-x-3 \end{gathered}[/tex]
since the area is above the line, and the line is continuous:
[tex]y\ge-x-3[/tex]
