The field inside a running track is made up of arectangle that is 84.39 m long and 73 m wide, together with a half-circle at each endThe track is 9.76 m wide all the way around. What is the distance around the outside of the track?Exact answer.

Answer:
(168.78 + 92.52π) m
Explanation:
The distance around the outside of the track is equal to two times the length of the rectangle added to the distance of two semi-circles.
So, two times the length of the rectangle is equal to
2 x 84.39 m = 168.78 m
On the other hand, the two semicircles form one circle and its perimeter is equal to
[tex]C=\pi d[/tex]Where d is the diameter of the semicircles. Taking into account the figure, the diameter is the width of the rectangle added to two times the width of the track, so
d = 73 m + 2(9.76m)
d = 73 m + 19.52 m
d = 92.52 m
Then the perimeter of the circle is
[tex]C=\pi(92.52m)=92.52\pi\text{ m}[/tex]Now, the total distance around the inside of the track is
168.78 m + 92.52π m = (168.78 + 92.52π) m