The zeros of the function are x = 1/2, 1
Explanation:The given function is:
[tex]y=2x^2-3x+1[/tex]This can be factorized as shown below
[tex]\begin{gathered} y=2x^2-2x-x-1 \\ \\ y=2x(x-1)-1(x-1) \\ \\ y=(2x-1)(x-1) \end{gathered}[/tex]To find the zeros of the function, let y = 0
[tex]\begin{gathered} 2x-1=0 \\ 2x=1 \\ x=\frac{1}{2} \\ \\ \\ x-1=0 \\ x=1 \end{gathered}[/tex]The zeros of the function are x = 1/2, 1
