Statement Problem: Assume that the population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% coincidence interval.
[tex]n=36,\bar{x}=59.9\sec ,s=4.3\sec [/tex]
Solution:
The margin of error can be approximated using the formula;
[tex]\begin{gathered} MOE_{\gamma}=z_{\gamma}\times\sqrt[]{\frac{\sigma^2}{n}} \\ z_{\gamma}=1.96_{} \\ \sigma=4.3 \\ n=36 \end{gathered}[/tex]
Thus;
[tex]\begin{gathered} MOE_{\gamma}=1.96\times\sqrt[]{\frac{4.3^2}{36}} \\ MOE_{\gamma}=1.4047 \end{gathered}[/tex]
Then, we would approximate to one decimal place, we have;
The margin of error is;
[tex]MOE_{\gamma}=1.4[/tex]
CORRECT ANSWER: 1.4 seconds
