Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a diamond for the second card drawn, if the first card, drawn with replacement, was a club? Express your answer as a fraction or a decimal rounded to four decimal places

Respuesta :

Given:

Two cards are drawn without replacement from a standard deck of 52 playing cards.

Required:

Find the probability of choosing a diamond for the second card drawn, if the first card, drawn with replacement, was a club.

Explanation:

The total number of cards in the deck = 52

The number of diamonds cards = 13

The number of club cards = 13

The probability of an event is given by the formula:

[tex]P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}[/tex]

The probability that the first card is a club:

[tex]\begin{gathered} =\frac{13}{52} \\ =\frac{1}{4} \end{gathered}[/tex]

If the drawn first card is not replaced then the left card is = 51

The probability that the second card is a diamond :

[tex]=\frac{13}{51}[/tex]

Now the probability of choosing two cards, if the first is a club and the second is a diamond:

[tex]\begin{gathered} =\frac{1}{4}\times\frac{13}{51} \\ =\frac{13}{204} \\ =0.0637 \end{gathered}[/tex]

Final answer:

The required answer is 0.0637.