[tex]\begin{gathered} \frac{4}{6m^2}-\frac{5-m^2}{4m}=\frac{4\cdot2-(5-m^2)\cdot3m}{12m^2}=\frac{8-(15m-3m^3)}{12m^2}= \\ =\frac{8-15m-3m^3}{12m^2} \end{gathered}[/tex]
B. The domain of a function is the set that contains every possible value for the independent variable (in this case, m). Given that you cannot divide by zero then
[tex]\begin{gathered} 12m^2\ne0 \\ m^2\ne0 \\ m\ne0 \end{gathered}[/tex]
Then, the domain is all real numbers except zero.
C. The expression in the denominator must be set equal to zero because you can't divide by zero.
