Since the total sections of the spinner are 8
Since the numbers on sections from 1 to 8
1, 2, 3, 4, 5, 6, 7, 8
The multiples of 2 are: 2, 4, 6, 8
Then the probability of multiples of 2 is
[tex]P(M.2)=\frac{4}{8}=\frac{1}{2}[/tex]
The multiples of 3 are: 3, 6
Then the probability of multiples of 3 is
[tex]P(M.3)=\frac{2}{8}=\frac{1}{4}[/tex]
Since we need both, then
[tex]P(M.2\cap M.3)=\frac{1}{2}\times\frac{1}{4}=\frac{1}{8}[/tex]
The answer is 1/8
