For the exponential equation given;
[tex]7^x=88[/tex]
We shall use the natural logarithm to evaluate as follows;
[tex]\begin{gathered} x=\frac{\ln (88)}{\ln (7)} \\ \ln 88=4.477 \\ \ln 7=1.946 \\ x=\frac{4.477}{1.946} \\ x=2.30089 \\ x\approx2.301\text{ (to 3 decimal places)} \end{gathered}[/tex]
ANSWER:
The value of x equals 2.301 (rounded to 3 decimal places)
