Theorem: A line parallel to one side of a triangle divides the other two proportionately.In the figure below, segment DE is parallel to segment BC and segment EF is parallel to AB:Which statement can be proved true using the given theorem?Segment BF = 16Segment BD = 20Segment BD = 15Segment BF = 32

Theorem A line parallel to one side of a triangle divides the other two proportionatelyIn the figure below segment DE is parallel to segment BC and segment EF i class=

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Answer:

Segment BD = 15

Explanation:

If DE is parallel to BC, DE divides the segments AC and AB proportionally, so we can write the following equation:

[tex]\frac{BD}{18}=\frac{20}{24}[/tex]

So, solving for BD, we get:

[tex]\begin{gathered} \frac{BD}{18}\times18=\frac{20}{24}\times18 \\ BD=15 \end{gathered}[/tex]

In the same way, since EF is parallel to AB, we can write the following relationship

[tex]\frac{BF}{30}=\frac{24}{20}[/tex]

So, solving for BF, we get:

[tex]\begin{gathered} \frac{BF}{30}\times30=\frac{24}{20}\times30 \\ BF=36 \end{gathered}[/tex]

Therefore, using the theorem, we get that BD is 15 and BF is 36. Then, the answer is:

Segment BD = 15