First, draw the figure with the coordinate points.
Now, find the distance between points: (-2,2) and (4,4)
[tex]D=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex][tex]D=\sqrt[]{(4-(-2))^2+(4-2)^2}=\sqrt[]{6^2+2^2}=\sqrt[]{40}=6.32[/tex]
We have the length of the rectangle.
To find the width, calculate the distance between points (-2,2) and (-1,-1)
[tex]D=\sqrt[]{(-1-(-2))^2+(-1-2)^2}=\sqrt[]{(-1+2)^2+(-3)^2}=\sqrt[]{1+9}=\sqrt[]{10}=3.16[/tex]
Finally, we have:
Length: 6.32
Width: 3.16
Perimeter of a rectangle:
P = 2w+2L
P = 2 (6.32)+ 2 (3.16) = 18.97 = 19
