a) The diagram representing the scenario is shown below
The spring experiences ossilations. The number of ossilations is the period The formula for calculating the period is expressed as
T = 2 x pi x square root of (m/k)
where
T is the period
m is the mass of the grape
k is the spring constant
From the information given,
T = 0.48
k = 650
pi = 3.14
By substituting these values into the formula, we have
[tex]\begin{gathered} 0.48\text{ = 2}\times3.14\times\sqrt[]{\frac{m}{650}} \\ \sqrt[]{\frac{m}{650}}\text{ = }\frac{0.48}{2\times3.14}=\text{ 0.076} \\ \text{Squaring both sides of the equation, we have} \\ \frac{m}{650}=0.005776 \\ m\text{ = 650 }\times0.005776 \\ m\text{ = }3.75 \end{gathered}[/tex]The mass of the grape is 3.75kg
b) Weight = mass x acceleration due to gravity
If acceleration due to gravity = 10m/s^2,
Then
Weight = 3.75 x 10 = 37.5N
