Recall that the inner angles of a triangle add up 180 degrees, then we can set the following equation for the given triangle:
[tex]\begin{gathered} 4x+7+3x+13+90=180 \\ \end{gathered}[/tex]solving for x we get:
[tex]\begin{gathered} 7x+110=180 \\ 7x=180-110=70 \\ x=10 \end{gathered}[/tex]With the value of x=10, we compute the angles:
4x+7 =47 degrees
3x+13= 43 degrees
Finally the angles of the triangle are:
[tex]47^o,43^o,90^o[/tex]