We have the following:
[tex]\frac{1}{f}=\frac{1}{d}+\frac{1}{d_0}[/tex]replacing:
[tex]\begin{gathered} \frac{1}{f}=\frac{1}{10}+\frac{1}{3} \\ \frac{1}{f}=0.1+0.33 \\ \frac{1}{f}=0.43 \\ \frac{1}{0.43}=f \\ f=\frac{1}{0.43}=2.31 \end{gathered}[/tex]the local length is 2.31 cm