Answer:
Graph A
Explanation:
The equation of a circle has the following form:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Where (h, k) are the coordinates of the center and r is the radius of the circle.
So, if the equation is:
[tex](x+3)^2+(y-1)^2=4_{}[/tex]
We can rewrite the expression to get:
[tex](x-(-3))^2+(y-1)^2=2^2[/tex]
Now, if we compare the equations, we can identify that the center is the point (-3, 1) and the radius is 2.
Therefore, the only option that satisfies both conditions is A. So, the answer is graph A.
