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Assume the random variable X is normally distributed, with mean j = 49 and standard deviation o = 8. Find the 12th percentile.The 12th percentile is(Round to two decimal places as needed)

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ANSWER:

STEP-BY-STEP EXPLANATION:

Given:

mean (µ) = 49

standard deviation (σ) = 8

To calculate the value of z for the 12th percentile we do the following:

[tex]\begin{gathered} P(ZValue of z at 12 percentile is -1.175, therefore z = -1.175.

Now, using z-score formula,

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