Given that,
The mass of marble A, m₁=0.08 kg
The mass of marble B, m₂=0.05 kg
The initial velocity of marble A, u₁=0.5 m/s
As the marble B was at rest, the initial velocity of marble B is u₂=0 m/s
The final velocity of marble A, v₁=-0.1 m/s
Let the final velocity of marble B be v₂.
According to the law of conservation of momentum, the total momentum before the collision is equal to the total after the collision.
Therefore
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]On rearranging the above equation,
[tex]v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}[/tex]On substituting the known values in the above equation,
[tex]\begin{gathered} v_2=\frac{0.08\times0.5+0.05\times0-0.08\times-0.1}{0.05} \\ =\frac{0.048}{0.05} \\ =0.96\text{ m/s} \end{gathered}[/tex]Therefore the
