20. Assume that X has a normal distribution, and find the indicated probabilityThe mean is u - 60,0 and the standard deviation is o = 4.0,Find the probability that X is less than 53.0.

Respuesta :

Recall that the Normal Distribution Formula is given by the z-score:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

Where μ is the mean and σ is the standard deviation.

Substitute μ=60.0, σ=4.0, and X=53.0 into the formula:

[tex]z=\frac{53.0-60.0}{4.0}=-\frac{7}{4}[/tex]

It then follows that:

[tex]P(X<53)=P(z<-\frac{7}{4})[/tex]

Next, check this in the normal distribution table, to get:

[tex]P(X<53)=P(z<-\frac{7}{4})=0.0401[/tex]

The answer is 0.0401.