In this problem, we can apply ratios to find the amount of boric acid in the solution.
We know that the ratio of boric acid to distilled water is 1:25. So, we can set up a proportion:
[tex]\frac{\text{borc acid}}{\text{water}}=\frac{1}{25}[/tex]Since we have a total of 900 mL of water, we can add the value of water and let x represent the boric acid:
[tex]\frac{x}{900}=\frac{1}{25}[/tex]Next, we can solve the proportion by cross multiplying:
[tex]\begin{gathered} 25\cdot x=900\cdot1 \\ 25x=900 \end{gathered}[/tex]Finally, we can divide by 25:
[tex]\begin{gathered} \frac{25x}{25}=\frac{900}{25} \\ \\ x=36 \end{gathered}[/tex]So, there are 36mL of boric acid.
